2x^2+3=212x2+3=21

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Solution for 2x^2+3=212x2+3=21 equation: 



2x^2+3=212x^2+3=21

We move all terms to the left:

2x^2+3-(212x^2+3)=0

We get rid of parentheses

2x^2-212x^2-3+3=0

We add all the numbers together, and all the variables

-210x^2=0

a = -210; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·(-210)·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{0}{-420}=0$

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